#! /usr/bin/env python3 # def knapsack_rational_test ( ): #*****************************************************************************80 # ## knapsack_rational_test() tests knapsack_rational(). # # Licensing: # # This code is distributed under the MIT license. # # Modified: # # 21 November 2024 # # Author: # # John Burkardt # import numpy as np import platform print ( '' ) print ( 'knapsack_rational_test():' ) print ( ' python version: ' + platform.python_version ( ) ) print ( ' numpy version: ' + np.version.version ) print ( ' Test knapsack_rational().' ) n = 5 v = np.array ( [ 24, 13, 23, 15, 16 ] ) w = np.array ( [ 12, 7, 11, 8, 9 ] ) d = v / w k = 26 print ( '' ) print ( 'knapsack_rational_tester():' ) print ( ' knapsack_rational() solves the rational knapsack problem.' ) print ( '' ) print ( ' Object Value Weight Density' ) print ( '' ) for i in range ( 0, n ): print ( ' %6d %7d %7d %7.3f' % ( i, v[i], w[i], d[i] ) ) index = np.argsort ( d ) index = np.flip ( index ) print ( ' Sort by density in descending order' ) v = v[index] w = w[index] d = d[index] print ( '' ) print ( ' After reordering by Density:' ) print ( '' ) print ( ' Object Value Weight Density' ) print ( '' ) for i in range ( 0, n ): print ( ' %6d %7d %7d %7.3f' % ( i, v[i], w[i], d[i] ) ) print ( '' ) print ( ' Weight limit is ', k ) s, vmax, wmax = knapsack_rational ( n, v, w, k ) print ( '' ) print ( ' Object Choice Value Weight Density' ) print ( '' ) for i in range ( 0, n ): print ( '%6d %7.3f %7d %7d %7.3f' \ % ( i, s[i], s[i] * v[i], s[i] * w[i], v[i] / w[i] ) ) print ( '' ) print ( ' Total:%7.3f %7d %7d %7.3f' % ( np.sum(s), vmax, wmax, vmax / wmax ) ) # # Terminate. # print ( '' ) print ( 'knapsack_rational_test():' ) print ( ' Normal end of execution.' ) return def knapsack_rational ( n, v, w, k ): #*****************************************************************************80 # ## knapsack_rational() solves the rational knapsack problem. # # Discussion: # # The rational knapsack problem is a generalization of the 0/1 knapsack # problem. It is mainly used to derive a bounding function for the # 0/1 knapsack problem. # # The 0/1 knapsack problem is as follows: # # Given: # a set of N objects, # a profit P(I) and weight W(I) associated with each object, # and a weight limit MASS_LIMIT, # Determine: # a set of choices X(I) which are 0 or 1, that maximizes the profit # P = Sum ( 1 <= I <= N ) P(I) * X(I) # subject to the constraint # Sum ( 1 <= I <= N ) W(I) * X(I) <= MASS_LIMIT. # # By contrast, the rational knapsack problem allows the values X(I) # to be any value between 0 and 1. A solution for the rational knapsack # problem is known. Arrange the objects in order of their "profit density" # ratios P(I)/W(I), and then take in order as many of these as you can. # If you still have "room" in the weight constraint, then you should # take the maximal fraction of the very next object, which will complete # your weight limit, and maximize your profit. # # If should be obvious that, given the same data, a solution for # the rational knapsack problem will always have a profit that is # at least as high as for the 0/1 problem. Since the rational knapsack # maximum profit is easily computed, this makes it a useful bounding # function. # # Note that this routine assumes that the objects have already been # arranged in order of the "profit density". # # Licensing: # # This code is distributed under the MIT license. # # Modified: # # 24 December 2015 # # Author: # # John Burkardt # # Reference: # # Donald Kreher, Douglas Simpson, # Combinatorial Algorithms, # CRC Press, 1998, # ISBN: 0-8493-3988-X, # LC: QA164.K73. # # Input: # # integer N, the number of objects. # # real P(N), the "profit" or value of each object. # The entries of P are assumed to be nonnegative. # # real W(N), the "weight" or cost of each object. # The entries of W are assumed to be nonnegative. # # real K, the weight limit of the chosen objects. # # Output: # # real X(N), the choice function for the objects. # 0.0, the object was not taken. # 1.0, the object was taken. # R, where 0 < R < 1, a fractional amount of the object was taken. # # real MASS, the total mass of the objects taken. # # real PROFIT, the total profit of the objects taken. # import numpy as np s = np.zeros ( n, dtype = float ) vmax = 0 wmax = 0 for i in range ( 0, n ): if ( k <= wmax ): s[i] = 0 elif ( wmax + w[i] <= k ): s[i] = 1 wmax = wmax + w[i] vmax = vmax + v[i] else: s[i] = ( k - wmax ) / w[i] wmax = k vmax = vmax + s[i] * v[i] return s, vmax, wmax def timestamp ( ): #*****************************************************************************80 # ## timestamp() prints the date as a timestamp. # # Licensing: # # This code is distributed under the MIT license. # # Modified: # # 06 April 2013 # # Author: # # John Burkardt # import time t = time.time ( ) print ( time.ctime ( t ) ) return None if ( __name__ == '__main__' ): timestamp ( ) knapsack_rational_test ( ) timestamp ( )