10 May 2025 01:24:52 PM zero_itp_test(): C version Test zero_itp(), which seeks a root of a function F(X) in an interval [A,B]. f_01(x) = sin ( x ) - x / 2 A Z B F(A) F(Z) F(B) 1.000000 1.895494 2.000000 3.414710e-01 -2.220446e-14 -9.070257e-02 Number of calls to F = 8 Tolerance epsi = 1.49012e-08 Parameters k1 = 0.2, k2 = 2, n0 = 1 f_02(x) = 2 * x - exp ( - x ) A Z B F(A) F(Z) F(B) 0.000000 0.351734 1.000000 -1.000000e+00 6.363410e-11 1.632121e+00 Number of calls to F = 8 Tolerance epsi = 1.49012e-08 Parameters k1 = 0.2, k2 = 2, n0 = 1 f_03(x) = x * exp ( - x ) A Z B F(A) F(Z) F(B) -1.000000 0.000000 0.500000 -2.718282e+00 2.513422e-12 3.032653e-01 Number of calls to F = 8 Tolerance epsi = 1.49012e-08 Parameters k1 = 0.133333, k2 = 2, n0 = 1 f_04(x) = exp ( x ) - 1 / ( 100 * x * x ) A Z B F(A) F(Z) F(B) 0.000100 0.095345 20.000000 -9.999990e+05 3.377484e-07 4.851652e+08 Number of calls to F = 31 Tolerance epsi = 1.49012e-08 Parameters k1 = 0.0100001, k2 = 2, n0 = 1 f_05(x) = (x+3) * (x-1) * (x-1) A Z B F(A) F(Z) F(B) -5.000000 -3.000000 2.000000 -7.200000e+01 0.000000e+00 5.000000e+00 Number of calls to F = 2 Tolerance epsi = 1.49012e-08 Parameters k1 = 0.0285714, k2 = 2, n0 = 1 User has requested additional verbose output. step [a, b] x f(x) 0 [1,2] f(1.5)=-0.125 1 [1.5,2] f(1.56515)=0.268999 2 [1.5,1.56515] f(1.52152)=0.000827384 3 [1.5,1.52152] f(1.52128)=-0.00056417 f_06(x) = x^3 - x - 2 A Z B F(A) F(Z) F(B) 1.000000 1.521402 2.000000 -2.000000e+00 1.315442e-04 4.000000e+00 Number of calls to F = 4 Tolerance epsi = 0.0005 Parameters k1 = 0.2, k2 = 2, n0 = 1 zero_itp_test(): Normal end of execution. 10 May 2025 01:24:52 PM